Verified Solution • 2025–26 Session moderate

QJEEM25Ph3207: JEE Main 2025 Physics - Class 12 JEEM25Ph3207 Solution: A series LCR circuit is connected to an alternating source of…

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is I0I_0 . If the value of resistance R becomes twice of its initial value then amplitude of current at resonance will be

Multiple Choice Options

  • A I02\frac{\mathrm{I}_0}{2}
  • B I02\frac{\mathrm{I}_0}{\sqrt{2}}
  • C 2I02 \mathrm{I}_0
  • D I0\mathrm{I_0}

Step-by-Step Verified Solution

Initially, I0=εmR\mathrm{I}_0=\frac{\varepsilon_{\mathrm{m}}}{\mathrm{R}}

Finally, I01=εm2R=I02I_0^1=\frac{\varepsilon_m}{2 R}=\frac{I_0}{2}

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