Verified Solution • 2025–26 Session moderate

QJEEM25Ph2f25: JEE Main 2025 Physics - Class 11 JEEM25Ph2f25 Solution: A solid sphere and a hollow sphere of the same mass and of same …

A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an inclined plane. Let the time taken to reach the bottom by the solid sphere and the hollow sphere be t1t_1 and t2t_2 , respectively, then

Multiple Choice Options

  • A t1<t2t_1< t_2
  • B t1=2t2t_1=2 t_2
  • C t1>t2t_1 >t_2
  • D t1=t2t_1=t_2

Step-by-Step Verified Solution

JEE Main 2025 (Online) 24th January Evening Shift Physics - Rotational Motion Question 3 English Explanation

amp;t=2ℓacmamp;acm=gsin⁡θ1+IcmMR2amp;a1=acm1=5 gsin⁡θ7….. Solid amp;a2=acm2=3 gsin⁡θ5…. Hollow amp;a1gt;a2amp;t1lt;t2\begin{aligned}&amp; \mathrm{t}=\sqrt{\frac{2 \ell}{\mathrm{a}_{\mathrm{cm}}}} \\&amp; \mathrm{a}_{\mathrm{cm}}=\frac{\mathrm{g} \sin \theta}{1+\frac{\mathrm{I}_{\mathrm{cm}}}{\mathrm{MR}^2}} \\&amp; \mathrm{a}_1=\mathrm{a}_{\mathrm{cm}_1}=\frac{5 \mathrm{~g} \sin \theta}{7} \ldots . . \text { Solid } \\&amp; \mathrm{a}_2=\mathrm{a}_{\mathrm{cm}_2}=\frac{3 \mathrm{~g} \sin \theta}{5} \ldots . \text { Hollow } \\&amp; \mathrm{a}_1&gt;\mathrm{a}_2 \\&amp; \mathrm{t}_1&lt;\mathrm{t}_2\end{aligned}

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