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QJEEM25Ph2c0c: JEE Main 2025 Physics - Class 11 JEEM25Ph2c0c Solution: Two soap bubbles of radius 2 cm and 4 cm , respectively, are in …

Two soap bubbles of radius 2 cm and 4 cm , respectively, are in contact with each other. The radius of curvature of the common surface, in cm , is _________.

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r=r1⋅r2r1−r2=2⋅44−2=4 cm\mathrm{r}=\frac{\mathrm{r}_1 \cdot \mathrm{r}_2}{\mathrm{r}_1-\mathrm{r}_2}=\frac{2 \cdot 4}{4-2}=4 \mathrm{~cm}

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