QJEEM25Ph0f33: JEE Main 2025 Physics - Class 11 JEEM25Ph0f33 Solution: A solid sphere is rolling without slipping on a horizontal…

$\begin{aligned}& \frac{\text { Linear KE }}{\text { Rotational K.E }}=\frac{\frac{1}{2} \mathrm{mv}_{\mathrm{cm}}^2}{\frac{1}{2} \mathrm{I} \omega^2} \\& \frac{\mathrm{mv}_{\mathrm{cm}}^2}{\frac{2}{5} \mathrm{mR}^2 \omega^2}=\frac{5}{2} \quad(\mathrm{~V}=\omega \mathrm{R})\end{aligned}$