Verified Solution • 2025–26 Session moderate

QJEEM25Ph0c45: JEE Main 2025 Physics - Class 11 JEEM25Ph0c45 Solution: The kinetic energy of translation of the molecules in 50 g of…

The kinetic energy of translation of the molecules in 50 g of CO2\text{CO}_2 gas at 17°C is :

Multiple Choice Options

  • A 4205.5 J
  • B 3582.7 J
  • C 3986.3 J
  • D 4102.8 J

Step-by-Step Verified Solution

amp;(KE)Transsational =[32KT]× no. of molecule amp; No. of molecule =[5044×6.023×1023]amp;(KE)Transsational =4108.644 J\begin{aligned}& (\mathrm{KE})_{\text {Transsational }}=\left[\frac{3}{2} \mathrm{KT}\right] \times \text { no. of molecule } \\& \text { No. of molecule }=\left[\frac{50}{44} \times 6.023 \times 10^{23}\right] \\& (\mathrm{KE})_{\text {Transsational }}=4108.644 \mathrm{~J}\end{aligned}

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