Verified Solution • 2025–26 Session moderate

QJEEM25Ph07f1: JEE Main 2025 Physics - Class 12 JEEM25Ph07f1 Solution: A coil of area A and N tums is rotating with angular velocity…

A coil of area A and N tums is rotating with angular velocity to in a uniform magnetic field B⃗\vec{B} about an axis perpendicular to B⃗\vec{B} . Magnetic flux φ\varphi and induced emf ε\varepsilon across it, at an instant when B⃗\vec{B} is parallel to the plane of coil, are :

Multiple Choice Options

  • A φ = AB, φ = NABω
  • B φ = AB, φ = 0
  • C φ = 0, ε = 0
  • D φ = 0, ε = NABω

Step-by-Step Verified Solution

JEE Main 2025 (Online) 29th January Morning Shift Physics - Electromagnetic Induction Question 7 English Explanation

amp;ϕamp;=BAN⋅cos⁡(ωt)εamp;=−dϕdt=BAω N⋅sin⁡(ωt)amp; When B is parallel to plane, ω‾‾t=π2amp;⇒ϕ=0,ε=BAω N\begin{aligned}&\begin{aligned}\phi & =\mathrm{BAN} \cdot \cos (\omega \mathrm{t}) \\\varepsilon & =\frac{-\mathrm{d} \phi}{\mathrm{dt}}=\mathrm{BA} \omega \mathrm{~N} \cdot \sin (\omega \mathrm{t})\end{aligned}\\&\text { When } B \text { is parallel to plane, } \underline{\underline{\omega}} \mathrm{t}=\frac{\pi}{2}\\&\Rightarrow \phi=0, \varepsilon=\mathrm{BA} \omega \mathrm{~N}\end{aligned}

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