Verified Solution • 2025–26 Session moderate

QJEEM25Mae93a: JEE Main 2025 Mathematics - Class 12 JEEM25Mae93a Solution: One die has two faces marked 1 , two faces marked 2 , one face…

One die has two faces marked 1 , two faces marked 2 , one face marked 3 and one face marked 4 . Another die has one face marked 1 , two faces marked 2 , two faces marked 3 and one face marked 4. The probability of getting the sum of numbers to be 4 or 5 , when both the dice are thrown together, is

Multiple Choice Options

  • A 23\frac{2}{3}
  • B 35\frac{3}{5}
  • C 49\frac{4}{9}
  • D 12\frac{1}{2}

Step-by-Step Verified Solution

a=\mathrm{a}= number or dice 1

b=\mathrm{b}= number on dice 2

(a,b)=(1,3),(3,1),(2,2),(2,3),(3,2),(1,4),(4,1)(a, b)=(1,3),(3,1),(2,2),(2,3),(3,2),(1,4),(4,1)

Required probability

amp;=26×26+16×16+26×26+26×26+16×26+26×16+16×26amp;=1836=12\begin{aligned}& =\frac{2}{6} \times \frac{2}{6}+\frac{1}{6} \times \frac{1}{6}+\frac{2}{6} \times \frac{2}{6}+\frac{2}{6} \times \frac{2}{6}+\frac{1}{6} \times \frac{2}{6}+\frac{2}{6} \times \frac{1}{6}+\frac{1}{6} \times \frac{2}{6} \\& =\frac{18}{36}=\frac{1}{2}\end{aligned}

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