QJEEM25Mae829: JEE Main 2025 Mathematics - Class 11 JEEM25Mae829 Solution: The number of ways, 5 boys and 4 girls can sit in a row so that …

A : number of ways that all boys sit together $=5!\times 5!$

B : number of ways if no 2 boys

sit together $=4!\times 5!$

$\mathrm{A} \cap \mathrm{B}=\phi$

Required no. of ways $=5!\times 5!+4!\times 5!=17280$