Verified Solution • 2025–26 Session moderate

QJEEM25Mac608: JEE Main 2025 Mathematics - Class 11 JEEM25Mac608 Solution: The relation and is even is:

The relation R={(x,y):x,y∈ZR=\{(x, y): x, y \in \mathbb{Z} and x+yx+y is even }\} is:

Multiple Choice Options

  • A reflexive and transitive but not symmetric
  • B reflexive and symmetric but not transitive
  • C an equivalence relation
  • D symmetric and transitive but not reflexive

Step-by-Step Verified Solution

R={(x,y):x,y∈zR=\{(x, y): x, y \in z and x+yx+y is even }\}

reflexive x+x=2xx+x=2 x even

symmetric of x+yx+y is even, then (y+x)(y+x) is also even

transitive of x+y\mathrm{x}+\mathrm{y} is even &y+z\& \mathrm{y}+\mathrm{z} is even then x+zx+z is also even

So, relation is an equivalence relation.

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