QJEEM25Mabac2: JEE Main 2025 Mathematics - Class 11 JEEM25Mabac2 Solution: The number of 3 -digit numbers, that are divisible by 2 and 3 , …

No, of 3 digits $=999-99=900$

No. of 3 digit numbers divisible by 2 & 3 i.e. by 6

$\frac{900}{6}=150$

No. of 3 digit numbers divisible by 4 & 9 i.e. by 36

$\frac{900}{36}=25$

$\therefore$ No of 3 digit numbers divisible by $2 \& 3$ but not by $4 \& 9$

$150-25=125$