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QJEEM25Mab690: JEE Main 2025 Mathematics - Class 11 JEEM25Mab690 Solution: Let and . Then the domain of is

Let f(x)=log⁡exf(x)=\log _{\mathrm{e}} x and g(x)=x4−2x3+3x2−2x+22x2−2x+1g(x)=\frac{x^4-2 x^3+3 x^2-2 x+2}{2 x^2-2 x+1} . Then the domain of f∘gf \circ g is

Multiple Choice Options

  • A (0,∞)(0, \infty)
  • B [1,∞)[1, \infty)
  • C R\mathbb{R}
  • D [0,∞)[0, \infty)

Step-by-Step Verified Solution

amp;f(x)=ln⁡xamp;g(x)=x4−2x3+3x2−2x+22x2−2x+1amp;Dg∈Ramp;Df∈(0,∞)\begin{aligned}& f(x)=\ln x \\& g(x)=\frac{x^4-2 x^3+3 x^2-2 x+2}{2 x^2-2 x+1} \\& D_g \in R \\& D_f \in(0, \infty)\end{aligned}

For D_{f o g} \Rightarrow g(x)>0

amp;x4−2x3+3x2−2x+22x2−2x+1gt;0amp;⇒x4−2x3+3x2−2x+2gt;0\begin{aligned}& \frac{x^4-2 x^3+3 x^2-2 x+2}{2 x^2-2 x+1}>0 \\& \Rightarrow x^4-2 x^3+3 x^2-2 x+2>0\end{aligned}

Clearly \mathrm{x}<0 satisfies which are included in option (1) only.

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