Verified Solution • 2025–26 Session moderate

QJEEM25Ma9d29: JEE Main 2025 Mathematics - Class 11 JEEM25Ma9d29 Solution: The number of different 5 digit numbers greater than 50000 that …

The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0 , 1,2,3,4,5,6,71,2,3,4,5,6,7 , such that the sum of their first and last digits should not be more than 8 , is

Multiple Choice Options

  • A 5720
  • B 5719
  • C 4608
  • D 4607

Step-by-Step Verified Solution

Case I 5−−−05{ }_{---} 0

Case II 5−−−15{ }_{---} 1

5amp;25amp;36amp;06amp;16amp;27amp;0\begin{array}{ll}5 & 2 \\5 & 3 \\6 & 0 \\6 & 1 \\6 & 2 \\7 & 0\end{array}

Case IX 7−−−17{ }_{---} 1

9×(8×8×8)=46089 \times(8 \times 8 \times 8)=4608 but 50000 is not included, so total numbers 4608−1=46074608-1=4607

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