Verified Solution • 2025–26 Session moderate

QJEEM25Ma736c: JEE Main 2025 Mathematics - Class 12 JEEM25Ma736c Solution: is:

\lim _\limits{x \rightarrow 0} \operatorname{cosec} x\left(\sqrt{2 \cos ^2 x+3 \cos x}-\sqrt{\cos ^2 x+\sin x+4}\right) is:

Multiple Choice Options

  • A 115\frac{1}{\sqrt{15}}
  • B 125\frac{1}{2 \sqrt{5}}
  • C 00
  • D −125-\frac{1}{2 \sqrt{5}}

Step-by-Step Verified Solution

amp;lim⁡x→0cosec⁡x(2cos⁡2x+3cos⁡x−cos⁡2x+sin⁡x+4)amp;lim⁡x→0cosec⁡(cos⁡2x+3cos⁡x−sin⁡x−4)(2cos⁡2x+3cos⁡x+cos⁡2x+sin⁡x+4)amp;lim⁡x→01sin⁡x(cos⁡2x+3cos⁡x−4)−sin⁡x(2cos⁡2x+3cos⁡x+cos⁡2x+sin⁡x+4)amp;lim⁡x→0(cos⁡x+4)(cos⁡x−1)−sin⁡xsin⁡x(2cos⁡2x+3cos⁡x+cos⁡2x+sin⁡x+4)amp;lim⁡x→0−2sin⁡2x2(cos⁡x+4)−2sin⁡x2cos⁡x22sin⁡x2cos⁡x2(2cos⁡2x+3cos⁡x+cos⁡2x+sin⁡x+4)amp;lim⁡x→0−(sin⁡xx2(cos⁡x+4)+cos⁡x2)cos⁡x2(2cos⁡2x+3cos⁡x+cos⁡2x+sin⁡x+4)amp;−125\begin{aligned}& \lim _{x \rightarrow 0} \operatorname{cosec} x\left(\sqrt{2 \cos ^2 x+3 \cos x}-\sqrt{\cos ^2 x+\sin x+4}\right) \\& \lim _{x \rightarrow 0} \frac{\operatorname{cosec}\left(\cos ^2 x+3 \cos x-\sin x-4\right)}{\left(\sqrt{2 \cos ^2 x+3 \cos x}+\sqrt{\cos ^2 x+\sin x+4}\right)} \\& \lim _{x \rightarrow 0} \frac{1}{\sin x} \frac{\left(\cos ^2 x+3 \cos x-4\right)-\sin x}{\left(\sqrt{2 \cos ^2 x+3 \cos x}+\sqrt{\cos ^2 x+\sin x+4}\right)} \\& \lim _{x \rightarrow 0} \frac{\left(\cos ^x+4\right)(\cos x-1)-\sin x}{\sin x\left(\sqrt{2 \cos ^2 x+3 \cos x}+\sqrt{\cos ^2 x+\sin x+4}\right)} \\& \lim _{x \rightarrow 0} \frac{-2 \sin ^2 \frac{x}{2}(\cos x+4)-2 \sin \frac{x}{2} \cos \frac{x}{2}}{2 \sin \frac{x}{2} \cos \frac{x}{2}\left(\sqrt{2 \cos ^2 x+3 \cos x}+\sqrt{\cos ^2 x+\sin x+4}\right)} \\& \lim _{x \rightarrow 0} \frac{-\left(\sin ^x \frac{x}{2}(\cos x+4)+\cos \frac{x}{2}\right)}{\cos \frac{x}{2}\left(\sqrt{2 \cos ^2 x+3 \cos x}+\sqrt{\cos ^2 x+\sin x+4}\right)} \\& -\frac{1}{2 \sqrt{5}}\end{aligned}

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