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QJEEM25Ma6688: JEE Main 2025 Mathematics - Class 11 JEEM25Ma6688 Solution: The focus of the parabola is the centre of the circle of radius …

The focus of the parabola y2=4x+16y^2=4 x+16 is the centre of the circle CC of radius 5 . If the values of λ\lambda , for which C passes through the point of intersection of the lines 3x−y=03 x-y=0 and x+λy=4x+\lambda y=4 , are λ1\lambda_1 and \lambda_2, \lambda_1<\lambda_2 , then 12λ1+29λ212 \lambda_1+29 \lambda_2 is equal to ________ .

Step-by-Step Verified Solution

y2=4(x+4)

Equation of circle

(x+3)2+y2=25

Passes through the point of intersection of two lines 3x−y=03 x-y=0 and x+λy=4x+\lambda y=4 which is (43λ+1,123λ+1)\left(\frac{4}{3 \lambda+1}, \frac{12}{3 \lambda+1}\right) , after solving with circle, we get

λ=−76,112λ1+29λ2−14+29=15

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