Verified Solution • 2025–26 Session moderate

QJEEM25Ma36fc: JEE Main 2025 Physics - Class 11 JEEM25Ma36fc Solution: Let and . Let and be two lines. If the line passes through the…

Let a⃗=i^+2j^+k^\vec{a}=\hat{i}+2 \hat{j}+\hat{k} and b⃗=2i^+7j^+3k^\vec{b}=2 \hat{i}+7 \hat{j}+3 \hat{k} . Let L1:r→=(−i^+2j^+k^)+λa⃗,λ∈R\mathrm{L}_1 : \overrightarrow{\mathrm{r}}=(-\hat{i}+2 \hat{j}+\hat{k})+\lambda \vec{a}, \mathrm{\lambda} \in \mathbf{R} and L2:r→=(j^+k^)+μb⃗,μ∈R\mathrm{L}_2: \overrightarrow{\mathrm{r}}=(\hat{j}+\hat{k})+\mu \vec{b}, \mu \in \mathrm{R} be two lines. If the line L3\mathrm{L}_3 passes through the point of intersection of L1\mathrm{L}_1 and LyL_y and is parallel to a⃗+b⃗\vec{a}+\vec{b} , then L3L_3 passes through the point :

Multiple Choice Options

  • A (−1,−1,1)(-1, -1, 1)
  • B (2,8,5)(2, 8, 5)
  • C (8,26,12)(8, 26, 12)
  • D (5,17,4)(5, 17, 4)

Step-by-Step Verified Solution

amp;L1:r→=(−i^+2j^+k^)+λ(i^+2j^+k^)amp;⇒r→=(λ−1)i^+2(λ+1)j^+(λ+1)k^amp;L2:r→=(j^+k^)+μ(2i^+7j^+3k^)amp;⇒r→=2μi^+(1+7μ)j^+(1+3μ)k^\begin{aligned}& L_1: \overrightarrow{\mathrm{r}}=(-\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}}) \\& \Rightarrow \overrightarrow{\mathrm{r}}=(\lambda-1) \hat{\mathrm{i}}+2(\lambda+1) \hat{\mathrm{j}}+(\lambda+1) \hat{\mathrm{k}} \\& L_2: \overrightarrow{\mathrm{r}}=(\hat{\mathrm{j}}+\hat{\mathrm{k}})+\mu(2 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}) \\& \Rightarrow \overrightarrow{\mathrm{r}}=2 \mu \hat{\mathrm{i}}+(1+7 \mu) \hat{\mathrm{j}}+(1+3 \mu) \hat{\mathrm{k}}\end{aligned}

For point of intersection equating respective components

amp;amp;⇒λ−1=2μ....... (1)amp;2(λ+1)=1+7μ...... (2)amp;λ+1=1+3μ..... (3)amp; We get \begin{aligned}&\begin{aligned}& \Rightarrow \lambda-1=2 \mu \quad\text{....... (1)}\\& 2(\lambda+1)=1+7 \mu \quad\text{...... (2)}\\& \lambda+1=1+3 \mu \quad\text{..... (3)}\end{aligned}\\&\text { We get }\end{aligned}

amp;⇒λ=3 and μ=1amp;⇒a→+b→=3i^+9j^+4k^amp;L3:r→=2i^+8j^+4k^+α(3i^+9j^+4k^)amp; For α=2,r→=8i^+26j^+12k^\begin{aligned}& \Rightarrow \lambda=3 \text { and } \mu=1 \\& \Rightarrow \overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}=3 \hat{\mathrm{i}}+9 \hat{\mathrm{j}}+4 \hat{\mathrm{k}} \\& L_3: \overrightarrow{\mathrm{r}}=2 \hat{\mathrm{i}}+8 \hat{\mathrm{j}}+4 \hat{\mathrm{k}}+\alpha(3 \hat{\mathrm{i}}+9 \hat{\mathrm{j}}+4 \hat{\mathrm{k}}) \\& \text { For } \alpha=2, \overrightarrow{\mathrm{r}}=8 \hat{\mathrm{i}}+26 \hat{\mathrm{j}}+12 \hat{\mathrm{k}}\end{aligned}

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