Verified Solution • 2025–26 Session moderate QJEEM25Ma0819: JEE Main 2025 Mathematics - Class 12 JEEM25Ma0819 Solution cos(sin−135+sin−1513+sin−13365)\cos \left(\sin ^{-1} \frac{3}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{33}{65}\right)cos(sin−153+sin−1135+sin−16533) is equal to: Multiple Choice Options A 3365\frac{33}{65}6533 B 1 C 3265\frac{32}{65}6532 D 0 Step-by-Step Verified Solution amp;cos(sin−135+sin−1513+sin−13365)amp;cos(tan−134+tan−1512+tan−13356)amp;cos(tan−1(34+5121+34⋅512)+tan−13356)amp;cos(tan−15633+cot−15633)amp;cos(π2)=0\begin{aligned}& \cos \left(\sin ^{-1} \frac{3}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{33}{65}\right) \\& \cos \left(\tan ^{-1} \frac{3}{4}+\tan ^{-1} \frac{5}{12}+\tan ^{-1} \frac{33}{56}\right) \\& \cos \left(\tan ^{-1}\left(\frac{\frac{3}{4}+\frac{5}{12}}{1+\frac{3}{4} \cdot \frac{5}{12}}\right)+\tan ^{-1} \frac{33}{56}\right) \\& \cos \left(\tan ^{-1} \frac{56}{33}+\cot ^{-1} \frac{56}{33}\right) \\& \cos \left(\frac{\pi}{2}\right)=0\end{aligned}amp;cos(sin−153+sin−1135+sin−16533)amp;cos(tan−143+tan−1125+tan−15633)amp;cos(tan−1(1+43⋅12543+125)+tan−15633)amp;cos(tan−13356+cot−13356)amp;cos(2π)=0 Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring