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QJEEM25Chff18: JEE Main 2025 Chemistry - Class 12 JEEM25Chff18 Solution: Consider the following low-spin complexes The sum of the…

Consider the following low-spin complexes

K3[Co(NO2)6],K4[Fe(CN)6],K3[Fe(CN)6],Cu2[Fe(CN)6] and Zn2[Fe(CN)6]\mathrm{K}_3\left[\mathrm{Co}\left(\mathrm{NO}_2\right)_6\right], \mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right], \mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right], \mathrm{Cu}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right] \text { and } \mathrm{Zn}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right]

The sum of the spin-only magnetic moment values of complexes having yellow colour is ________ B.M. (answer in nearest integer)

Step-by-Step Verified Solution

Yellow coloured \& low spin complex are K3[Co(NO2)6]& K4[Fe(CN)6]\mathrm{K}_3\left[\mathrm{Co}\left(\mathrm{NO}_2\right)_6\right] \& \mathrm{~K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]

(I) K3[Co(NO2)6]\quad \mathrm{K}_3\left[\mathrm{Co}\left(\mathrm{NO}_2\right)_6\right]

Co+3⇒[Ar]3 d6\mathrm{Co}^{+3} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^6

In presence of ligand field

JEE Main 2025 (Online) 29th January Evening Shift Chemistry - Coordination Compounds Question 16 English Explanation 1

 Magnetic moment amp;=n(n+2)BMamp;=0 BM\begin{aligned}\text { Magnetic moment } & =\sqrt{\mathrm{n}(\mathrm{n}+2)} \mathrm{BM} \\& =0 \mathrm{~BM}\end{aligned}

(II) amp;K4[Fe(CN)6]amp;Fe+2⇒[Ar]3 d6\begin{aligned}\text{(II) }\quad & \mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \\& \mathrm{Fe}^{+2} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^6\end{aligned}

In presence of ligand field

JEE Main 2025 (Online) 29th January Evening Shift Chemistry - Coordination Compounds Question 16 English Explanation 2

 Magnetic moment amp;=n(n+2)BMamp;=0 BM\begin{aligned}\text { Magnetic moment } & =\sqrt{\mathrm{n}(\mathrm{n}+2)} \mathrm{BM} \\& =0 \mathrm{~BM}\end{aligned}

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