Verified Solution • 2025–26 Session moderate

QJEEM25Chfec3: JEE Main 2025 Chemistry - Class 11 JEEM25Chfec3 Solution: In the sulphur estimation, 0.20 g of a pure organic compound…

In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is __________ ×10−1%\times 10^{-1} \% .

(Molar mass : O=16, S=32,Ba=137\mathrm{O}=16, \mathrm{~S}=32, \mathrm{Ba}=137 in g mol−1\mathrm{g} ~\mathrm{mol}^{-1} )

Step-by-Step Verified Solution

Organic Compound ⟶BaSO4\longrightarrow \mathrm{BaSO}_4

0.20 gm \qquad \qquad\qquad 0.40 gm

amp;0.40233 mol(BaSO4)amp;0.40233 mol (Sulphur) amp;0.40233×32gm (sulphur) \begin{aligned}& \frac{0.40}{233} \mathrm{~mol}\left(\mathrm{BaSO}_4\right) \\& \frac{0.40}{233} \mathrm{~mol} \text { (Sulphur) } \\& \frac{0.40}{233} \times 32 \mathrm{gm} \text { (sulphur) }\end{aligned}

% S=0.40×32233×1000.20=27.5%\% \mathrm{~S}=\frac{\frac{0.40 \times 32}{233} \times 100}{0.20}=27.5 \% or 275×10−1%275 \times 10^{-1} \%

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