QJEEM25Cheb76: JEE Main 2025 Chemistry - Class 12 JEEM25Cheb76 Solution: The standard reduction potential values of some of the p-block…

The strength of an oxidizing agent is related to its standard reduction potential. A higher (more positive) standard reduction potential indicates a stronger oxidizing agent because the species is more likely to gain electrons (be reduced).

Given the options:

Option A: $E^o_{\text{Sn}^{4+}/\text{Sn}^{2+}} = +1.15 \text{ V}$

Option B: $E^o_{\text{Al}^{3+}/\text{Al}} = -1.66 \text{ V}$

Option C: $E^o_{\text{Pb}^{4+}/\text{Pb}^{2+}} = +1.67 \text{ V}$

Option D: $E^o_{\text{Tl}^{3+}/\text{Tl}} = +1.26 \text{ V}$

The species with the highest standard reduction potential is the strongest oxidizing agent. In this case, Option C, $E^o_{\text{Pb}^{4+}/\text{Pb}^{2+}} = +1.67 \text{ V}$ , is the highest value among the given potentials.

Therefore, lead(IV) ion ( $\text{Pb}^{4+}$ ) with a reduction potential of $+1.67 \text{ V}$ is the strongest oxidizing agent among the given options.