Verified Solution • 2025–26 Session moderate

QJEEM25Chdecf: JEE Main 2025 Chemistry - Class 12 JEEM25Chdecf Solution: For a Mg

For a Mg | Mg2+ (aq) || Ag+ (aq) | Ag the correct Nernst Equation is:

Multiple Choice Options

  • A Ecell =Ecell o−RT2 Fln⁡[Ag+]2[Mg2+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}-\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Ag}^{+}\right]^2}{\left[\mathrm{Mg}^{2+}\right]}
  • B Ecell =Ecell o−RT2 Fln⁡[Ag+][Mg2+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}-\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Ag}^{+}\right]}{\left[\mathrm{Mg}^{2+}\right]}
  • C Ecell =Ecell o−RT2 Fln⁡[Mg2+][Ag+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}-\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Mg}^{2+}\right]}{\left[\mathrm{Ag}^{+}\right]}
  • D Ecell =Ecell o+RT2 Fln⁡[Ag+]2[Mg2+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}+\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Ag}^{+}\right]^2}{\left[\mathrm{Mg}^{2+}\right]}

Step-by-Step Verified Solution

For the cell: Mg∣Mg2+(aq)∥Ag+(aq)∣Ag\text{Mg} \mid \text{Mg}^{2+} \text{(aq)} \parallel \text{Ag}^{+} \text{(aq)} \mid \text{Ag}

Cell Reaction:

Mg(s)+2Ag(aq)+⇌2Ag(s)+Mg(aq)+2

Nernst Equation Analysis:

Standard form: Ecell=Ecell∘−RT2Fln⁡[Mg+2][Ag+]2By log property [−ln⁡(x/y)=+ln⁡(y/x)]:⇒Ecell=Ecell∘+RT2Fln⁡[Ag+]2[Mg+2]

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