Verified Solution • 2025–26 Session moderate

QJEEM25Chdb8a: JEE Main 2025 Chemistry - Class 11 JEEM25Chdb8a Solution: Standard entropies of and are 70, 50 and respectively. The…

Standard entropies of X2,Y2\mathrm{X}_2, \mathrm{Y}_2 and XY5\mathrm{XY}_5 are 70, 50 and 110 J K−1 mol−1110 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} respectively. The temperature in Kelvin at which the reaction

12X2+52Y2⇌XY5ΔH⊖=−35 kJ mol−1

will be at equilibrium is __________ (Nearest integer)

Step-by-Step Verified Solution

12X2+52Y2⇌XY5Δ SRxn0=110−[(12×70)+(52×50)]=110−160=−50JK−1 mol−1ΔG0=0 at eqb ΔG0=ΔH0−TΔ S00=−35000−T(−50)T=700 Kelvin

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