Verified Solution • 2025–26 Session moderate

QJEEM25Chc96f: JEE Main 2025 Chemistry - Class 11 JEEM25Chc96f Solution: The hydrocarbon with molar mass and carbon has _______ degree…

The hydrocarbon (X)(\mathrm{X}) with molar mass 80 g mol−180 \mathrm{~g} \mathrm{~mol}^{-1} and 90%90 \% carbon has _______ degree of unsaturation.

Step-by-Step Verified Solution

Mass of carbon =80×90100=72gm=\frac{80 \times 90}{100}=72 \mathrm{gm}

Number of C-atoms =7212=6=\frac{72}{12}=6

Mass of hydrogen =80×10800=8gm=\frac{80 \times 10}{800}=8 \mathrm{gm}

Number of H -atoms =81=8=\frac{8}{1}=8

So molecular formula C6H8\mathrm{C}_6 \mathrm{H}_8

D.U. =6+1−8/2=7−4=3=6+1-8 / 2=7-4=3

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