Verified Solution • 2025–26 Session moderate

QJEEM25Chc561: JEE Main 2025 Chemistry - Class 11 JEEM25Chc561 Solution: If (diamond (graphite) C (diamond) C (graphite) at constant…

If C\quad C (diamond )→C) \rightarrow C (graphite) +X kJ mol−1+X \mathrm{~kJ} \mathrm{~mol}^{-1}

C (diamond) +O2( g)→CO2( g)+YkJmol−1+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Y} \mathrm{kJ} \mathrm{mol}{ }^{-1}

C (graphite) +O2( g)→CO2( g)+ZkJmol−1+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Z} \mathrm{kJ} \mathrm{mol}^{-1}

at constant temperature. Then

Multiple Choice Options

  • A −X = Y + Z
  • B X = Y − Z
  • C X = −Y + Z
  • D X = Y + Z

Step-by-Step Verified Solution

X=Y−Z\mathrm{X=Y-Z}

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