Verified Solution • 2025–26 Session moderate

QJEEM25Chc11a: JEE Main 2025 Chemistry - Class 12 JEEM25Chc11a Solution: One mole of the octahedral complex compound gives 3 moles of…

One mole of the octahedral complex compound Co(NH3)5Cl3\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}_3 gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with excess of AgNO3\mathrm{AgNO}_3 solution to yield two moles of AgCl(s)\mathrm{AgCl}_{(\mathrm{s})} . The structure of the complex is:

Multiple Choice Options

  • A [Co(NH3)5Cl]Cl2\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2
  • B [Co(NH3)4Cl]⋅Cl2⋅NH3\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}\right] \cdot \mathrm{Cl}_2 \cdot \mathrm{NH}_3
  • C [Co(NH3)3Cl3]⋅2NH3\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \cdot 2 \mathrm{NH}_3
  • D [Co(NH3)4Cl2]⋅Cl⋅NH3\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \cdot \mathrm{Cl} \cdot \mathrm{NH}_3

Step-by-Step Verified Solution

[Co(NH3)5Cl]Cl2→[Co(NH3)5Cl]2+( aq. )+2Cl−(aq.) ⏟3 ions in water \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \rightarrow \underbrace{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right]^{2+}(\text { aq. })+2 \mathrm{Cl}^{-} \text {(aq.) }}_{3 \text { ions in water }}

[Co(NH3)5Cl]Cl2 (aq.) )+2AgNO3 (aq.) →[Co(NH3)5Cl](NO3)2( aq. )+2AgCl( s)

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