Verified Solution • 2025–26 Session moderate

QJEEM25Ch96b2: JEE Main 2025 Chemistry - Class 12 JEEM25Ch96b2 Solution: Match List - I with List - II. .tg…

Match List - I with List - II.

List - I
(Transition metal ion)		 List - II
(Spin only magnetic moment (B.M.))
(A) Ti3+\mathrm{Ti}^{3+} (I) 3.87
(B) V2+\mathrm{V}^{2+} (II) 0.00
(C) Ni2+\mathrm{Ni}^{2+} (III) 1.73
(D) Sc3+\mathrm{Sc}^{3+} (IV) 2.84

Choose the correct answer from the options given below :

Multiple Choice Options

  • A (A)−(III),(B)−(I),(C)−(IV),(D)−(II)\mathrm{(A) -(III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})
  • B (A)−(II),(B)−(IV),(C)−(I),(D)−(III)(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})
  • C (A)−(III),(B)−(I),(C)−(II),(D)−(IV)(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})
  • D (A)−(IV),(B)−(II),(C)−(III),(D)−(I)(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})

Step-by-Step Verified Solution

Sc+3=3 d∘amp;∴μspin =0 V+2=3 d3amp;∴μspin =3.87 B.M. Ni+2=3 d8amp;∴μspin =2.84 B.M. \begin{array}{ll}\mathrm{Sc}^{+3}=3 \mathrm{~d}^{\circ} & \therefore \mu_{\text {spin }}=0 \\\mathrm{~V}^{+2}=3 \mathrm{~d}^3 & \therefore \mu_{\text {spin }}=3.87 \text { B.M. } \\\mathrm{Ni}^{+2}=3 \mathrm{~d}^8 & \therefore \mu_{\text {spin }}=2.84 \text { B.M. }\end{array}

Ti+3=3 d1∴μspin=1.73 B.M\mathrm{Ti}^{+3}=3 \mathrm{~d}^1 \quad \therefore \mu_{\mathrm{spin}}=1.73 \mathrm{~B} . \mathrm{M}

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