Verified Solution • 2025–26 Session moderate

QJEEM25Ch8f26: JEE Main 2025 Chemistry - Class 11 JEEM25Ch8f26 Solution: Some gas was kept in a sealed container at a pressure of 1 atm…

Some CO2\mathrm{CO}_2 gas was kept in a sealed container at a pressure of 1 atm and at 273 K . This entire amount of CO2\mathrm{CO}_2 gas was later passed through an aqueous solution of Ca(OH)2\mathrm{Ca}(\mathrm{OH})_2 . The excess unreacted Ca(OH)2\mathrm{Ca}(\mathrm{OH})_2 was later neutralized with 0.1 M of 40 mL HCl . If the volume of the sealed container of CO2\mathrm{CO}_2 was xx , then xx is ____________ cm3\mathrm{cm}^3 (nearest integer). [Given : The entire amount of CO2( g)\mathrm{CO}_2(\mathrm{~g}) reacted with exactly half the initial amount of Ca(OH)2\mathrm{Ca}(\mathrm{OH})_2 present in the aqueous solution.]

Step-by-Step Verified Solution

Let moles of CO2=n\mathrm{CO}_2=\mathrm{n}

moles of Ca(OH)2\mathrm{Ca}(\mathrm{OH})_2

total initially =2n=2 \mathrm{n}

excess Ca(OH)2=n\mathrm{Ca}(\mathrm{OH})_2=\mathrm{n}

gm equivalent of Ca(OH)2=\mathrm{Ca}(\mathrm{OH})_2= gm equivalent of HCl

n×2=0.1×401000×1n=2×10−3

Volume of CO2=2×10−3×22400=44.8 cm3\mathrm{CO}_2=2 \times 10^{-3} \times 22400=44.8 \mathrm{~cm}^3

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