Verified Solution • 2025–26 Session moderate

QJEEM25Ch8cd2: JEE Main 2025 Chemistry - Class 11 JEEM25Ch8cd2 Solution: During " S " estimation, 160 mg of an organic compound gives…

During " S " estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is _________ %.

(Given molar mass in g mol−1\mathrm{g} \mathrm{~mol}^{-1} of Ba:137, S:32,O:16\mathrm{Ba}: 137, \mathrm{~S}: 32, {\mathrm{O}: 16} )

Step-by-Step Verified Solution

amp; Millimoles of BaSO4=466233=2 m molamp;% S=466233×32160×100=40%\begin{aligned}& \text { Millimoles of } \mathrm{BaSO}_4=\frac{466}{233}=2 \mathrm{~m} \mathrm{~mol} \\& \% \mathrm{~S}=\frac{\frac{466}{233} \times 32}{160} \times 100=40 \%\end{aligned}

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