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QJEEM25Ch814a: JEE Main 2025 Chemistry - Class 11 JEEM25Ch814a Solution: An ideal gas undergoes a cyclic transformation starting from…

JEE Main 2025 (Online) 28th January Evening Shift Chemistry - Thermodynamics Question 14 English

An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A→B→C→D→A as shown in the three cases above.

Choose the correct option regarding ΔU :

Multiple Choice Options

  • A ΔU( Case-III )>ΔU( Case-II )>ΔU( Case-I )\Delta \mathrm{U}(\text { Case-III })>\Delta \mathrm{U}(\text { Case-II })>\Delta \mathrm{U}(\text { Case-I })
  • B ΔU(\Delta \mathrm{U}( Case-I )>ΔU()>\Delta \mathrm{U}( Case-II )>ΔU()>\Delta \mathrm{U}( Case-III ))
  • C ΔU(\Delta \mathrm{U}( Case-I )=ΔU()=\Delta \mathrm{U}( Case-II )=ΔU()=\Delta \mathrm{U}( Case-III ))
  • D ΔU(\Delta \mathrm{U}( Case-I )>ΔU()>\Delta \mathrm{U}( Case-III )>ΔU()>\Delta \mathrm{U}( Case-II ))

Step-by-Step Verified Solution

As internal energy ' UU ' is a state function, its cyclic integral must be zero in a cyclic process

∴ΔU case (I)=ΔU case (II)=ΔU case ( III )\therefore \Delta U \text { case }(I)=\Delta U \text { case }(I I)=\Delta U \text { case }(\text { III })

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