Verified Solution • 2025–26 Session moderate

QJEEM25Ch6e2f: JEE Main 2025 Chemistry - Class 12 JEEM25Ch6e2f Solution: What is the freezing point depression constant of a solvent, 50 …

What is the freezing point depression constant of a solvent, 50 g of which contain 1 g non volatile solute (molar mass 256 g mol−1256 \mathrm{~g} \mathrm{~mol}^{-1} ) and the decrease in freezing point is 0.40 K ?

Multiple Choice Options

  • A 4.43 K kg mol−14.43 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}
  • B 3.72 K kg mol−13.72 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}
  • C 5.12 K kg mol−15.12 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}
  • D 1.86 K kg mol−11.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}

Step-by-Step Verified Solution

ΔTf=Kb⋅ m0.4=Kb125650×10−3 Kb=5.12 K kg/mol

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