Verified Solution • 2025–26 Session moderate

QJEEM25Ch5c32: JEE Main 2025 Chemistry - Class 11 JEEM25Ch5c32 Solution: The elemental composition of a compound is and . If the molar…

The elemental composition of a compound is 54.2%C,9.2%H54.2 \% \mathrm{C}, 9.2 \% \mathrm{H} and 36.6%O36.6 \% \mathrm{O} . If the molar mass of the compound is 132 g mol−1132 \mathrm{~g} \mathrm{~mol}^{-1} , the molecular formula of the compound is : [Given : The relative atomic mass of C:H:O=12:1:16\mathrm{C}: \mathrm{H}: \mathrm{O}=12: 1: 16 ]

Multiple Choice Options

  • A C4H8O2\mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_2
  • B C6H12O6\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6
  • C C4H9O3\mathrm{C}_4 \mathrm{H}_9 \mathrm{O}_3
  • D C6H12O3\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3

Step-by-Step Verified Solution

C:H:O54.212:9.2:36.6164.516:9.2:2.2874.5162.287:9.22.287:2.2872.2871.97:4.02:1

C2H4O⇒\mathrm{C}_2 \mathrm{H}_4 \mathrm{O} \Rightarrow Empirical formula

E.F. mass =24+4+16=44=24+4+16=44

and molar mass =132=132

 Hence molecular formula =(C2H4O)3=C6H12O3

Correct Option (3)

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