Verified Solution • 2025–26 Session moderate

QJEEM25Ch55b1: JEE Main 2025 Chemistry - Class 11 JEEM25Ch55b1 Solution: The molarity of a (mass/mass) aqueous solution of a monobasic…

The molarity of a 70%70 \% (mass/mass) aqueous solution of a monobasic acid (X) is _________ ×10−1\times 10^{-1} M (Nearest integer)

[Given: Density of aqueous solution of (X) is 1.25 g mL−11.25 \mathrm{~g} \mathrm{~mL}^{-1}

Molar mass of the acid is 70 g mol−170 \mathrm{~g} \mathrm{~mol}^{-1} ]

Step-by-Step Verified Solution

Assuming 100 gm solution contain 70 gm solute.

Volume of 100 gm solution will be 1001.25ml\frac{100}{1.25} \mathrm{ml} .

Molarity =70/70100/1.25×1000=12.5=\frac{70 / 70}{100 / 1.25} \times 1000=12.5 or 125×10−1125 \times 10^{-1}

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