Verified Solution • 2025–26 Session moderate

QJEEM25Ch4be0: JEE Main 2025 Chemistry - Class 12 JEEM25Ch4be0 Solution: Consider the following reactions K 2 Cr 2 O 7 → − H 2 O KOH […

Consider the following reactions

K2Cr2O7→−H2OKOH[ A]→−H2OH2SO4[ B]+K2SO4

The products [A][A] and [B][B] , respectively are :

Multiple Choice Options

  • A K2Cr(OH)6\mathrm{K}_2 \mathrm{Cr}(\mathrm{OH})_6 and Cr2O3\mathrm{Cr}_2 \mathrm{O}_3
  • B K2CrO4\mathrm{K}_2 \mathrm{CrO}_4 and Cr2O3\mathrm{Cr}_2 \mathrm{O}_3
  • C K2CrO4\mathrm{K}_2 \mathrm{CrO}_4 and K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7
  • D K2CrO4\mathrm{K}_2 \mathrm{CrO}_4 and CrO\mathrm{CrO}

Step-by-Step Verified Solution

K2Cr2O7→−H2OKOHK2CrO4 [A] →−H2OH2 S4K2Cr2O7 [B] +K2SO4\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{KOH}} \underset{\text { [A] }}{\mathrm{K}_2 \mathrm{CrO}_4} \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{H}_2 \mathrm{~S}_4} \underset{\text { [B] }}{\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7}+\mathrm{K}_2 \mathrm{SO}_4

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