QJEEM25Ch046a: JEE Main 2025 Chemistry - Class 12 JEEM25Ch046a Solution: Match List - I with List - II. List - I (Complex) List - II…

(A) $\left[\mathrm{MnBr}_4\right]^{2-}$

$\mathrm{Mn}^{+2} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5$

In presence of ligand field

$\Rightarrow \mathrm{sp}^3$ hybridization, paramagnetic in nature

(B) $\left[\mathrm{FeF}_6\right]^{3-}$

$${\mathrm{Fe}}^{+3}\Rightarrow [\mathrm{Ar}]3{\mathrm{d}}^5$$

In presence of ligand field

$\Rightarrow \mathrm{sp}^3 \mathrm{~d}^2$ hybridization, paramagnetic in nature

(C) $\left[\mathrm{Co}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$

$${\mathrm{Co}}^{+3}\Rightarrow [\mathrm{Ar}]3{\mathrm{d}}^6$$

In presence of ligand field

$\Rightarrow \mathrm{d}^2 \mathrm{sp}^3$ hybridization, diamagnetic in nature

$$\text{ (D) }[\mathrm{Ni}(\mathrm{CO}{)}_4]$$

$${\mathrm{Ni}}^0\Rightarrow [\mathrm{Ar}]3{\mathrm{d}}^{8}4{\mathrm{s}}^2$$

In presence of ligand field

$\Rightarrow \mathrm{sp}^3$ hybridization, diamagnetic in nature