Verified Solution • 2025–26 Session
hard
QJEEM_2024_24: JEE Main 2024 JEEM_2024_24 Solution: Ball released from height 10 m strikes ground and rebounds…
Ball released from height 10 m strikes ground and rebounds height 5 m. Find impulse imparted by ground while collision, given mass of ball is 100 g. (Take g = 10 m/s²).
Multiple Choice Options
- A (√2 - 1) Ns
- B (√2 + 2) Ns
- C (2√2 - 1) Ns
- D (√2 + 1) Ns
Step-by-Step Verified Solution
v1 = √(2g×10); v2 = √(2g×5); I = 0.1(v20 + v10) => I = (√2 + 1) Ns