QJEEM24Phfe94: JEE Main 2024 Physics - Class 12 JEEM24Phfe94 Solution: In Young's double slit experiment, light from two identical…

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QJEEM24Phfe94: JEE Main 2024 Physics - Class 12 JEEM24Phfe94 Solution: In Young's double slit experiment, light from two identical…

In Young's double slit experiment, light from two identical sources are superimposing on a screen. The path difference between the two lights reaching at a point on the screen is $7 λ / 4$ . The ratio of intensity of fringe at this point with respect to the maximum intensity of the fringe is :

Multiple Choice Options

A 12
B 34
C 13
D 14

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Accepted Answer

$\begin{aligned} Δ x = \frac{7 λ}{4} \\ ϕ = \frac{2 π}{λ} Δ x = \frac{2 π}{λ} \times \frac{7 λ}{4} = \frac{7 π}{2} \\ I = I_{max} \cos^{2} (\frac{ϕ}{2}) \\ \frac{I}{I_{max}} = \cos^{2} (\frac{ϕ}{2}) = \cos^{2} (\frac{7 π}{2 \times 2}) = \cos^{2} (\frac{7 π}{4}) \\ = \cos^{2} (2 π - \frac{π}{4}) \\ = \cos^{2} \frac{π}{4} \\ = \frac{1}{2} \end{aligned}$

QJEEM24Phfe94: JEE Main 2024 Physics - Class 12 JEEM24Phfe94 Solution: In Young's double slit experiment, light from two identical…

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