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QJEEM24Phfbfc: JEE Main 2024 Physics - Class 12 JEEM24Phfbfc Solution: Two resistance of 100 Ω and 200 Ω are connected in series with…

Two resistance of 100Ω and 200Ω are connected in series with a battery of 4 V and negligible internal resistance. A voltmeter is used to measure voltage across 100Ω resistance, which gives reading as 1 V. The resistance of voltmeter must be _______ Ω.

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JEE Main 2024 (Online) 30th January Evening Shift Physics - Current Electricity Question 39 English Explanation

Rv100Rv+100=20033Rv=2Rv+200Rv=200

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