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QJEEM24Phfb0b: JEE Main 2024 Physics - Class 12 JEEM24Phfb0b Solution: A ceiling fan having 3 blades of length each is rotating with…

A ceiling fan having 3 blades of length 80 cm80 \mathrm{~cm} each is rotating with an angular velocity of 1200 rpm\mathrm{rpm} . The magnetic field of earth in that region is 0.5G0.5 \mathrm{G} and angle of dip is 30∘30^{\circ} . The emf induced across the blades is Nπ×10−5 V\mathrm{N} \pi \times 10^{-5} \mathrm{~V} . The value of N\mathrm{N} is _________.

Step-by-Step Verified Solution

amp;Bv=Bsin⁡30=14×10−4amp;ω=2π×f=2π60×1200 rad/samp;ε=12BVωℓ2amp;=32π×10−5 V\begin{aligned}& B_v=B \sin 30=\frac{1}{4} \times 10^{-4} \\& \omega=2 \pi \times f=\frac{2 \pi}{60} \times 1200 \mathrm{~rad} / \mathrm{s} \\& \varepsilon=\frac{1}{2} B_V \omega \ell^2 \\& =32 \pi \times 10^{-5} \mathrm{~V}\end{aligned}

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