Verified Solution • 2025–26 Session moderate

QJEEM24Phf80b: JEE Main 2024 Physics - Class 12 JEEM24Phf80b Solution: The reading in the ideal voltmeter shown in the given circuit…

The reading in the ideal voltmeter (V)(\mathrm{V}) shown in the given circuit diagram is :

JEE Main 2024 (Online) 1st February Morning Shift Physics - Current Electricity Question 57 English

Multiple Choice Options

  • A 3 V3 \mathrm{~V}
  • B 10 V10 \mathrm{~V}
  • C 5 V5 \mathrm{~V}
  • D 0 V0 \mathrm{~V}

Step-by-Step Verified Solution

i=amp;Eeq req=8×58×0.2amp;I=25 Aamp;V=E−iramp;=5−0.2×25amp;=0\begin{aligned} \mathrm{i}= & \frac{\mathrm{E}_{\text {eq }}}{\mathrm{r}_{\mathrm{eq}}}=\frac{8 \times 5}{8 \times 0.2} \\\\ & \mathrm{I}=25 \mathrm{~A} \\\\ & V=\mathrm{E}-\mathrm{ir} \\\\ & =5-0.2 \times 25 \\\\ & =0\end{aligned}

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