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QJEEM24Phf657: JEE Main 2024 Physics - Class 12 JEEM24Phf657 Solution: Two cells are connected in opposition as shown. Cell is of emf…

Two cells are connected in opposition as shown. Cell E1\mathrm{E}_1 is of 8 V8 \mathrm{~V} emf and 2Ω2 \Omega internal resistance; the cell E2\mathrm{E}_2 is of 2 V2 \mathrm{~V} emf and 4Ω4 \Omega internal resistance. The terminal potential difference of cell E2\mathrm{E}_2 is __________ V.

JEE Main 2024 (Online) 30th January Morning Shift Physics - Current Electricity Question 36 English

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JEE Main 2024 (Online) 30th January Morning Shift Physics - Current Electricity Question 36 English Explanation

I=8−22+4=66=1 AI=\frac{8-2}{2+4}=\frac{6}{6}=1 \mathrm{~A}

Applying Kirchhoff from C to B

amp;VC−2−4×1=VBamp;VC−VB=6 Vamp;=6 V\begin{aligned}& V_C-2-4 \times 1=V_B \\\\& V_C-V_B=6 \mathrm{~V} \\\\& =6 \mathrm{~V}\end{aligned}

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