Verified Solution • 2025–26 Session moderate

QJEEM24Phf32f: JEE Main 2024 Physics - Class 12 JEEM24Phf32f Solution: A wire of resistance and length is cut into 5 equal parts. If…

A wire of resistance R\mathrm{R} and length L\mathrm{L} is cut into 5 equal parts. If these parts are joined parallely, then resultant resistance will be :

Multiple Choice Options

  • A 125R\frac{1}{25} \mathrm{R}
  • B 15R\frac{1}{5} R
  • C 25 R
  • D 5 R

Step-by-Step Verified Solution

Resistance of each part =R5=\frac{R}{5}

Total resistance =15×R5=R25=\frac{1}{5} \times \frac{\mathrm{R}}{5}=\frac{\mathrm{R}}{25}

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