Verified Solution • 2025–26 Session moderate

QJEEM24Pheb5b: JEE Main 2024 Physics - Class 11 JEEM24Pheb5b Solution: Two vessels and are of the same size and are at same…

Two vessels AA and BB are of the same size and are at same temperature. A contains 1 g1 \mathrm{~g} of hydrogen and BB contains 1 g1 \mathrm{~g} of oxygen. PA\mathrm{P}_{\mathrm{A}} and PB\mathrm{P}_{\mathrm{B}} are the pressures of the gases in A\mathrm{A} and B\mathrm{B} respectively, then PAPB\frac{P_A}{P_B} is:

Multiple Choice Options

  • A 4
  • B 32
  • C 8
  • D 16

Step-by-Step Verified Solution

amp;PAVAPBVB=nARTAnBRTBamp; Given VA=VBamp; And TA=TBamp;PAPB=nAnBamp;PAPB=1/21/32=16\begin{aligned}& \frac{\mathrm{P}_{\mathrm{A}} \mathrm{V}_{\mathrm{A}}}{\mathrm{P}_{\mathrm{B}} \mathrm{V}_{\mathrm{B}}}=\frac{\mathrm{n}_{\mathrm{A}} R T_{\mathrm{A}}}{\mathrm{n}_{\mathrm{B}} \mathrm{RT}_{\mathrm{B}}} \\& \text { Given } \mathrm{V}_{\mathrm{A}}=\mathrm{V}_{\mathrm{B}} \\& \text { And } \mathrm{T}_{\mathrm{A}}=\mathrm{T}_{\mathrm{B}} \\& \frac{\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\mathrm{B}}}=\frac{\mathrm{n}_{\mathrm{A}}}{\mathrm{n}_{\mathrm{B}}} \\& \frac{\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\mathrm{B}}}=\frac{1 / 2}{1 / 32}=16\end{aligned}

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