QJEEM24Phe6cd: JEE Main 2024 Physics - Class 12 JEEM24Phe6cd Solution: The disintegration energy Q for the nuclear fission of 235 U →…

The disintegration energy $$Q$$ for the nuclear fission of $${}^{235}\mathrm{U}\to {}^{140}\mathrm{Ce}+{}^{94}\mathrm{Zr}+n$$ is _______ $$\mathrm{MeV}$$.

Given atomic masses of $${}^{235}\mathrm{U}:235.0439u;{}^{140}\mathrm{Ce}:139.9054u,{}^{94}\mathrm{Zr}:93.9063u;n:1.0086u$$, Value of $$c^2=931\mathrm{MeV}/\mathrm{u}$$.