Verified Solution • 2025–26 Session moderate

QJEEM24Phe58b: JEE Main 2024 Physics - Class 11 JEEM24Phe58b Solution: The gravitational potential at a point above the surface of…

The gravitational potential at a point above the surface of earth is −5.12×107 J/kg-5.12 \times 10^7 \mathrm{~J} / \mathrm{kg} and the acceleration due to gravity at that point is 6.4 m/s26.4 \mathrm{~m} / \mathrm{s}^2 . Assume that the mean radius of earth to be 6400 km6400 \mathrm{~km} . The height of this point above the earth's surface is :

Multiple Choice Options

  • A 1600 km
  • B 1200 km
  • C 540 km
  • D 1000 km

Step-by-Step Verified Solution

−GMERE+h=−5.12×10−7-\frac{G M_E}{R_E+h}=-5.12 \times 10^{-7} .... (i)

GME(RE+h)2=6.4\frac{G M_E}{\left(R_E+h\right)^2}=6.4 ..... (ii)

By (i) and (ii)

⇒h=16×105 m=1600 km\Rightarrow h=16 \times 10^5 \mathrm{~m}=1600 \mathrm{~km}

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