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QJEEM24Phe245: JEE Main 2024 Physics - Class 11 JEEM24Phe245 Solution: If average depth of an ocean is and the bulk modulus of water…

If average depth of an ocean is 4000 m4000 \mathrm{~m} and the bulk modulus of water is 2×109 Nm−22 \times 10^9 \mathrm{~Nm}^{-2} , then fractional compression ΔVV\frac{\Delta V}{V} of water at the bottom of ocean is α×10−2\alpha \times 10^{-2} . The value of α\alpha is _______ (Given, g=10 ms−2,ρ=1000 kg m−3\mathrm{g}=10 \mathrm{~ms}^{-2}, \rho=1000 \mathrm{~kg} \mathrm{~m}^{-3} )

Step-by-Step Verified Solution

amp;B=−ΔP(ΔVV)amp;−(ΔVV)=ρghB=1000×10×40002×109amp;=2×10−2[−ve sign represent compression ]\begin{aligned}& \mathrm{B}=-\frac{\Delta \mathrm{P}}{\left(\frac{\Delta \mathrm{V}}{\mathrm{V}}\right)} \\& -\left(\frac{\Delta \mathrm{V}}{\mathrm{V}}\right)=\frac{\rho \mathrm{gh}}{\mathrm{B}}=\frac{1000 \times 10 \times 4000}{2 \times 10^9} \\& =2 \times 10^{-2}[-\mathrm{ve} \text { sign represent compression }]\end{aligned}

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