QJEEM24Phddf2: JEE Main 2024 Physics - Class 12 JEEM24Phddf2 Solution: At the centre of a half ring of radius R = 10   cm and…

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QJEEM24Phddf2: JEE Main 2024 Physics - Class 12 JEEM24Phddf2 Solution: At the centre of a half ring of radius R = 10   cm and…

At the centre of a half ring of radius $R = 10 cm$ and linear charge density $4 nC m^{- 1}$ , the potential is $x π V$ . The value of $x$ is _________.

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$\begin{aligned} V & = \frac{K Q}{R} \\ = \frac{9 \times 10^{9} \times 4 \times 10^{- 9} π R}{R} \\ = 36 π \end{aligned}$

QJEEM24Phddf2: JEE Main 2024 Physics - Class 12 JEEM24Phddf2 Solution: At the centre of a half ring of radius R = 10 &nbsp; cm and…

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QJEEM24Phddf2: JEE Main 2024 Physics - Class 12 JEEM24Phddf2 Solution: At the centre of a half ring of radius R = 10 cm and…