Verified Solution • 2025–26 Session moderate

QJEEM24Phdbff: JEE Main 2024 Physics - Class 11 JEEM24Phdbff Solution: Two thermodynamical processes are shown in the figure. The…

Two thermodynamical processes are shown in the figure. The molar heat capacity for process A and B are CA\mathrm{C}_{\mathrm{A}} and CB\mathrm{C}_{\mathrm{B}} . The molar heat capacity at constant pressure and constant volume are represented by CP\mathrm{C_P} and CV\mathrm{C_V} , respectively. Choose the correct statement.

JEE Main 2024 (Online) 30th January Morning Shift Physics - Heat and Thermodynamics Question 49 English

Multiple Choice Options

  • A CP>CB>CA>CV\mathrm{C_P>C_B>C_A>C_V}
  • B CP>CV>CA=CB\mathrm{C}_{\mathrm{P}}>\mathrm{C}_{\mathrm{V}}>\mathrm{C}_{\mathrm{A}}=\mathrm{C}_{\mathrm{B}}
  • C CA=0\mathrm{C}_{\mathrm{A}}=0 and CB=∞\mathrm{C}_{\mathrm{B}}=\infty
  • D CA=∞,CB=0\mathrm{C_A=\infty, C_B=0}

Step-by-Step Verified Solution

For process A\mathrm{A}

amp;log⁡P=γlog⁡V⇒P=Vγ,(γgt;1)amp;PV−γ= Constant \begin{aligned}& \log P=\gamma \log \mathrm{V} \Rightarrow \mathrm{P}=\mathrm{V}^\gamma,(\gamma>1) \\& P V^{-\gamma}=\text { Constant }\end{aligned}

CA=CV+R1+γC_A=C_V+\frac{R}{1+\gamma} ..... (i)

Likewise for process B→PV−1=\mathrm{B} \rightarrow P V^{-1}= Constant

amp;CB=Cv+R1+1amp;CB=Cv+R2..... (ii)amp;CP=Cv+R..... (iii)\begin{aligned}& C_B=C_v+\frac{R}{1+1} \\& C_B=C_v+\frac{R}{2} \quad \text{..... (ii)} \\& C_P=C_v+R \quad \text{..... (iii)}\end{aligned}

By (i), (ii) & (iii)

C_P>C_B>C_A>C_v [No answer matching]

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