QJEEM24Phd729: JEE Main 2024 Physics - Class 12 JEEM24Phd729 Solution: A wire of length 10   cm and radius 7 × 10 − 4   m…

A wire of length $$10\mathrm{cm}$$ and radius $$\sqrt{7}\times {10}^{-4}\mathrm{m}$$ connected across the right gap of a meter bridge. When a resistance of $$4.5\mathrm{\Omega }$$ is connected on the left gap by using a resistance box, the balance length is found to be at $$60\mathrm{cm}$$ from the left end. If the resistivity of the wire is $$\mathrm{R}\times {10}^{-7}\mathrm{\Omega }\mathrm{m}$$, then value of $$\mathrm{R}$$ is :