QJEEM24Phcae4: JEE Main 2024 Physics - Class 12 JEEM24Phcae4 Solution: In the given circuit, the breakdown voltage of the Zener diode…

Question

Verified Solution • 2025–26 Session moderate

In the given circuit, the breakdown voltage of the Zener diode is $3.0 V$ . What is the value of $I_{z}$ ?

JEE Main 2024 (Online) 29th January Morning Shift Physics - Semiconductor Question 25 English

Accepted Answer

JEE Main 2024 (Online) 29th January Morning Shift Physics - Semiconductor Question 25 English Explanation

$V_{z} = 3 V$

Let potential at $B = 0 V$

Potential at $E (V_{E}) = 10 V$

$\begin{aligned} V_{C} = V_{A} = 3 V \\ I_{z} + I_{1} = I \\ I = \frac{10 - 3}{1000} = \frac{7}{1000} A \\ I_{1} = \frac{3}{2000} A \end{aligned}$

Therefore $I_{z} = \frac{7 - 1.5}{1000} = 5.5 mA$

Step-by-Step Verified Solution