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QJEEM24Phc849: JEE Main 2024 Physics - Class 12 JEEM24Phc849 Solution: If the distance between object and its two times magnified…

If the distance between object and its two times magnified virtual image produced by a curved mirror is 15 cm15 \mathrm{~cm} , the focal length of the mirror must be:

Multiple Choice Options

  • A −10-10 cm
  • B −12-12 cm
  • C 15 cm
  • D 10/3 cm

Step-by-Step Verified Solution

JEE Main 2024 (Online) 29th January Evening Shift Physics - Geometrical Optics Question 33 English Explanation

amp;m=2=−vuamp;2=−(15−u)−uamp;2u=15−uamp;3u=15⇒u=5 cmamp;v=15−u=15−5=10 cmamp;1f=1v+1uamp;=110+1(−5)=1−210=−110amp;f=−10 cm\begin{aligned}& \mathrm{m}=2=\frac{-v}{u} \\& 2=\frac{-(15-u)}{-u} \\& 2 u=15-u \\& 3 u=15 \Rightarrow u=5 \mathrm{~cm} \\& v=15-u=15-5=10 \mathrm{~cm} \\& \frac{1}{f}=\frac{1}{v}+\frac{1}{u} \\& =\frac{1}{10}+\frac{1}{(-5)}=\frac{1-2}{10}=\frac{-1}{10} \\& f=-10 \mathrm{~cm}\end{aligned}

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