QJEEM24Phc848: JEE Main 2024 Physics - Class 12 JEEM24Phc848 Solution: Two identical conducting spheres P and S with charge Q on each, …

Question

Verified Solution • 2025–26 Session moderate

QJEEM24Phc848: JEE Main 2024 Physics - Class 12 JEEM24Phc848 Solution: Two identical conducting spheres P and S with charge Q on each, …

Two identical conducting spheres P and S with charge Q on each, repel each other with a force $16 N$ . A third identical uncharged conducting sphere $R$ is successively brought in contact with the two spheres. The new force of repulsion between $P$ and $S$ is :

Multiple Choice Options

A 1 N
B 6 N
C 12 N
D 4 N

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring

Accepted Answer

$\begin{aligned} F_{1} = \frac{K Q^{2}}{r^{2}} = 16 N \\ F_{2} = \frac{K (\frac{Q}{2}) (\frac{3}{4})}{r^{2}} = \frac{3}{8} \times 16 = 6 N \end{aligned}$

Final charges on spheres are $\frac{Q}{2}$ and $\frac{3 Q}{4}$ .

QJEEM24Phc848: JEE Main 2024 Physics - Class 12 JEEM24Phc848 Solution: Two identical conducting spheres P and S with charge Q on each, …

Multiple Choice Options

Step-by-Step Verified Solution

Related Learning Resources & Exam Preparation